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After taking the (1xx 2 ) factorHi I'm Piyush I'm obsessed by Maths It's my drug And here's your solution Solution 2 x = 3 y = (12) z = k 2 x = k, 3 y = k, (12) z = k 2 = k 1/x, 3 = k 1/y, 12 = k 1/z 12 = 2 2 x 3 k1/z = (k 1/x) 2 x k 1/y k1/z = k 1/x x 2 x k 1/ Since, (a m) n = a mn k1/z = k 2/x x k 1/y k1/z = k 2/x1/y Since, am x an = amn 1/z = 2/x 1/y, Since, bases are same ie base = kLooking for something else?
After completing the square, we can rewrite the equation as 4(x 21)2 (y 5) 16(z 1)2 = 37 This is a hyperboloid of 1 sheet which has been shifted Speci cally, its centralQuestion If 2x = 3y = 6z then Prove that 1/x 1/y 1/z=0 Solution 2x = 6 z ÞEx 32, 12 Given 3 8(x&y@z&w) = 8(x&6@−1&2w) 8(4&xy@zw&3) find the values of x, y, z and w 3 8(x&y@z&w) = 8(x&6@−1&2w) 8(4&xy@zw&3) 8




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Y log 3 = log k ;By using properties of determinants, show that determinant 1 x x^2 x^2 1 x x x^2 1 = (1x^3)^2 Ex 42 Q 12 # NCERT Q 12 By using properties of determinants, show that Post Answer Answers (1) D Divya Prakash Singh Give determinant Applying column transformation we get;Show transcribed image text Expert Answer Previous question Next question Transcribed Image Text from this Question lim xy yz^2 xz^2/x^2 y^2 z^4 (x, y, z) rightarrow (0, 0, 0) find the limit as (x, y, z) approaches (0, 0, 0) Get more help from Chegg Solve it with our calculus problem solver and calculator




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Ex 46, 11 Solve system of linear equations, using matrix method 2x y z = 1 x – 2y – z = 3/2 3y – 5z = 9 The system of equation is 2x y z = 1 x – 2y – z = 3/2 3y – 5z = 9 Writing above equation as AX = B 8(2&1&1@1&−2&−1@0&3&−5) 8(𝑥@𝑦@𝑧If 2x = 3y = 12z, Show that `1/Z=1/Y2/X`The solution is ((x),(y),(z))=((2),(1),(2)) Perform the Gauss Jordan Elimination on the Augmented Matrix A=((1,1,1,,1),(2,1,2,,1),(1,3,1,,1)) The pivot is in




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